NUST NET Mathematics — Permutations, Combinations and Probability
Permutations, Combinations and Probability is part of the FSc Mathematics course that NUST NET-Engineering draws on (Mathematics is 100 of the 200 MCQs). It breaks into 3 subtopics, and we hold 155 NET-pattern practice MCQs on it, each with a written explanation. Tap a subtopic below to practise just that.
Subtopics (3)
How Permutations, Combinations and Probability is tested
Across the 8 NET-pattern papers on ParhaiKrlo, Permutations, Combinations and Probability accounts for 61 questions. It appears in all 8, about 7.6 questions a paper. The heaviest was NUST NET Past Paper 06, with 8 questions, and the most recent is NUST NET Past Paper 07, with 7.
| Paper | Questions |
|---|---|
| NUST NET Past Paper 07 | 7 |
| NUST NET Past Paper 08 | 7 |
| NUST NET Past Paper 05 | 7 |
| NUST NET Past Paper 06 | 8 |
| NUST NET Past Paper 03 | 8 |
| NUST NET Past Paper 04 | 8 |
| NUST NET Past Paper 01 | 8 |
| NUST NET Past Paper 02 | 8 |
Permutations, Combinations and Probability MCQs from the NET-pattern papers
Try each one before opening the answer. Each comes with a short explanation.
- Q1 · NUST NET Past Paper 07 · Permutations, Combinations and Probability
The number of distinct arrangements of the letters of the word PAKISTAN is:
- A.40320
- B.20160
- C.10080
- D.5040
Show answer
Answer: B. 20160 — PAKISTAN has 8 letters with A repeated twice: 8!/2! = 20160.
- Q2 · NUST NET Past Paper 08 · Permutations, Combinations and Probability
The value of 0! + 1! + 2! + 3! is:
- A.9
- B.10
- C.6
- D.7
Show answer
Answer: B. 10 — 0! + 1! + 2! + 3! = 1 + 1 + 2 + 6 = 10.
- Q3 · NUST NET Past Paper 05 · Permutations, Combinations and Probability
How many 3-digit numbers with all digits different can be formed from the digits 1, 2, 3, 4, 5?
- A.60
- B.125
- C.10
- D.20
Show answer
Answer: A. 60 — ⁵P₃ = 5 × 4 × 3 = 60.