NUST NET Physics — Motion and Force
Motion and Force is part of the FSc Physics course that NUST NET-Engineering draws on (Physics is 60 of the 200 MCQs). It breaks into 4 subtopics, and we hold 97 NET-pattern practice MCQs on it, each with a written explanation. Tap a subtopic below to practise just that.
Subtopics (4)
How Motion and Force is tested
Across the 8 NET-pattern papers on ParhaiKrlo, Motion and Force accounts for 37 questions. It appears in all 8, about 4.6 questions a paper. The heaviest was NUST NET Past Paper 07, with 5 questions.
| Paper | Questions |
|---|---|
| NUST NET Past Paper 07 | 5 |
| NUST NET Past Paper 08 | 5 |
| NUST NET Past Paper 05 | 5 |
| NUST NET Past Paper 06 | 5 |
| NUST NET Past Paper 03 | 5 |
| NUST NET Past Paper 04 | 3 |
| NUST NET Past Paper 01 | 4 |
| NUST NET Past Paper 02 | 5 |
Motion and Force MCQs from the NET-pattern papers
Try each one before opening the answer. Each comes with a short explanation.
- Q1 · NUST NET Past Paper 07 · Motion and Force
A car starts from rest and accelerates uniformly at 2 m/s² for 10 s. The distance covered is:
- A.50 m
- B.20 m
- C.200 m
- D.100 m
Show answer
Answer: D. 100 m — s = ut + ½at² = 0 + ½(2)(10²) = 100 m.
- Q2 · NUST NET Past Paper 08 · Motion and Force
A stone is dropped from rest and falls freely for 4 s. The distance it falls is:
- A.40 m
- B.80 m
- C.160 m
- D.20 m
Show answer
Answer: B. 80 m — s = ½gt² = ½ × 10 × 16 = 80 m.
- Q3 · NUST NET Past Paper 05 · Motion and Force
A car moving at 20 m/s is brought to rest uniformly over 40 m. Its deceleration is:
- A.10 m/s²
- B.2.5 m/s²
- C.5 m/s²
- D.0.5 m/s²
Show answer
Answer: C. 5 m/s² — v² = u² − 2as: 0 = 400 − 80a ⇒ a = 5 m/s².