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9th Class Chemistry · Punjab Board · Chapter 2

Chapter 2: Atomic StructureLong Questions with Answers

12 long (comprehensive) questions of 9th Class Chemistry Chapter 2, Atomic Structure, answered in full with headings, diagrams and tables, including important board-paper questions beyond the book. Punjab Board new syllabus.

Chapter 2· Atomic Structure

Long Questions with Answers

Long answers, explained in full with headings. Learn the structure: definition, explanation, diagram or table, example.

Set A: Textbook comprehensive questions 6 questions

The long questions at the end of the chapter in your book.

Long Q 2.1

Explain the structure of a hydrogen atom.

Answer

The hydrogen atom is the simplest of all atoms. It has a tiny central nucleus with one proton and one electron revolving around it. Its atomic number is 1.

Nucleus

Rutherford showed that an atom has two portions: a tiny central portion called the nucleus and a relatively large area surrounding it called the extra-nuclear portion. Ordinary hydrogen ¹₁H is the only atom which does not have a neutron, so its nucleus is a single proton. Almost all its mass is in this proton, which is 1836 times heavier than the electron.

Electron: Bohr's model

In 1913, Niels Bohr proposed a model for the hydrogen atom. According to this model the electron can revolve around the nucleus in specific paths called orbits or shells. When the electron is revolving in one of these orbits, its energy is fixed. When it is present in the orbit closest to the nucleus (the K shell), its energy is minimum and it is called the ground state of the atom. The orbits further away possess successively greater energy, and the electron is not allowed to occupy a space in between the orbits.

+nucleusFirst shell (K)n = 1, E = E₁Second shell (L)n = 2, E = E₂Third shell (M)n = 3, E = E₃Fourth shell (N)n = 4, E = E₄E₄ > E₃ > E₂ > E₁the further the shell from the nucleus, the higher its energy
The electron of hydrogen is in the K shell in its ground state.

Transition of the electron

When energy is given to the atom, the electron jumps to a higher shell (an excited state). When it returns to the ground state it gives out the energy as light; this is why hydrogen gives light of definite colours.

Modern view

According to the modern approach, the electron is like a charged cloud around the nucleus whose location cannot be predicted with one hundred percent certainty; there is only a certain probability of finding it at a certain distance from the nucleus.

Isotopes of hydrogen

Hydrogen exists as three isotopes, hydrogen (protium) ¹₁H, deuterium ²₁H and tritium ³₁H. All have one proton and one electron, but 0, 1 and 2 neutrons. ²₁H has twice and ³₁H thrice the mass of ¹₁H. Tritium is radioactive.

Isotopes of hydrogenP=1Protium ¹₁HP=1N=1Deuterium ²₁HP=1N=2Tritium ³₁HIsotopes of carbonN=6P=6Carbon-12 ¹²₆CN=7P=6Carbon-13 ¹³₆CN=8P=6Carbon-14 ¹⁴₆C
Protium, deuterium and tritium.
IsotopeProtonsNeutronsElectrons
¹₁H101
²₁H111
³₁H121
Long Q 2.2

How does the theory of atomic structure explain the ionisation of atoms by a radioactive isotope?

Answer

Theory of atomic structure

An atom has a nucleus containing protons and neutrons, surrounded by electrons in shells. The electrons in the outer shell are furthest from the nucleus and held least firmly.

Ionisation by a radioactive source

Radiation emitted from a radioactive source causes atoms to ionise. For example, radiation emitted by the radioactive element radium-226 can remove electron or electrons from the atom. However, this ionising radiation should have enough energy to remove the tightly bound electron from the orbit of an atom. An electron can be lost because the ionising radiation collides with the atom and forces the electron away from the atom.

If an atom of sodium is hit by ionising radiation, it may lose an electron. This process converts the atom into a positively charged ion (cation):

Na —(energy)→ Na⁺ + e⁻

Formation of an anion

The electron set free may be captured by another atom, which then becomes a negatively charged ion (anion):

Cl + e⁻ → Cl⁻
Long Q 2.3

What is radioactivity? Explain any three applications of radioactive isotopes.

Answer

Radioactivity

The isotopes of the same element do not have the same physical properties. Several isotopes of the same elements exist whose nuclei are unstable. They emit excess energy in the form of radiation. This process of emission of radiation is called radioactivity and the isotope which emits energy is called a radioactive isotope. Tritium ³₁H is a radioactive isotope, while the other two isotopes of hydrogen are stable and do not emit any radiation.

Radioactive decay

When a radioactive element emits radiation, it is transformed into another chemical element. This process is called radioactive decay. The new element may be stable or may be radioactive so that it also emits radiation.

²³⁸₉₂U → ²³⁴₉₀Th + energy; ²³⁴₉₀Th → ²³⁴₉₁Pa + energy; ²¹⁰₈₃Bi → ²⁰⁶₈₁Tl + energy

1. Medical imaging and treatment

Radioactive isotopes are useful in medical imaging. Doctors use them to diagnose disease by injecting the patient with a small amount of radioactive fluid. Technetium-99m is used for diagnostic imaging across human organs like the brain and lungs. Doctors use a special camera to watch how the radioactive fluid moves. In medicine they are also used to treat many diseases, including cancer and thyroid disorders.

2. Radiocarbon dating (archaeology)

Radiocarbon dating is a method for finding out the age of a historical object containing organic material with the help of the radioactive isotope of carbon, ¹⁴₆C. The method involves measuring the proportion of ¹⁴C in a sample from a dead plant or animal, like a piece of wood or a bone, which provides information that can be used to calculate when the animal or plant died. The older the sample is, the less ¹⁴C is to be detected.

3. Industry and power generation

Radioactive isotopes are used to test the strength of metals and concrete mixtures. They are used to generate cheap nuclear power and to find oil fields.

Long Q 2.4

Find out the relative atomic mass of mercury from the following data: ¹⁹⁶Hg 0.0146 %, ¹⁹⁸Hg 10.02 %, ¹⁹⁹Hg 16.34 %, ²⁰⁰Hg 23.13 %, ²⁰¹Hg 13.22 %, ²⁰²Hg 29.80 %, ²⁰⁴Hg 6.85 %.

Answer

The relative atomic mass of an element can be calculated from the relative isotopic masses (m) and isotopic abundances (p):

Relative atomic mass = (m₁p₁ + m₂p₂ + m₃p₃ + …) ÷ 100
Isotopem × p
¹⁹⁶Hg196 × 0.0146 = 2.86
¹⁹⁸Hg198 × 10.02 = 1983.96
¹⁹⁹Hg199 × 16.34 = 3251.66
²⁰⁰Hg200 × 23.13 = 4626.00
²⁰¹Hg201 × 13.22 = 2657.22
²⁰²Hg202 × 29.80 = 6019.60
²⁰⁴Hg204 × 6.85 = 1397.40
Total19 938.70

Using the book's formula: 19 938.70 ÷ 100 = 199.39.

The abundances given add up to only 99.37 %, so dividing by their total gives the accurate value: 19 938.70 ÷ 99.37 = 200.6 (the accepted value for mercury is 200.59).

Check your book

In the exam, write the formula and the working above. The book's answer by its formula is 199.4; mention that the abundances total 99.37 %, which is why the accepted value is 200.6.

Long Q 2.5

(Investigative) How can scientists synthesise elements in the laboratory?

Answer

An element is fixed by its number of protons, so a new element is made by changing the nucleus. Ordinary chemical reactions only move electrons, so this needs nuclear reactions, carried out in particle accelerators and nuclear reactors. Technetium was the first element created by scientists in the laboratory.

1. Particle bombardment

Light particles (neutrons, protons, deuterons, alpha particles or carbon ions) are given very high energy in a particle accelerator and fired at a target of heavy atoms. When a particle enters a target nucleus, the number of protons changes and a new element forms.

Worked exampleFirst artificial element
  1. Molybdenum (42 protons) was bombarded with deuterons (1 proton + 1 neutron) in 1937.

AnswerTechnetium, element 43

2. Nuclear fusion

Two nuclei are made to join into one heavier nucleus, releasing energy. Superheavy elements (Z = 104 to 118) are made by fusing a beam of medium nuclei, such as calcium-48, with a heavy target such as californium.

3. Neutron capture and decay (in a nuclear reactor)

In a reactor, heavy nuclei absorb neutrons and then give out beta radiation, which turns a neutron into a proton. Uranium-238 becomes neptunium (Z = 93) and then plutonium (Z = 94) this way.

4. Nuclear fission

A heavy nucleus such as uranium-235 is split by a neutron into two lighter nuclei plus more neutrons and a great deal of energy. Fission produces lighter elements already known, and its neutrons drive the reactions above; it is the process used in nuclear power stations.

Note

Most elements beyond uranium (Z > 92) are man-made. Many superheavy elements last only fractions of a second before decaying.

Long Q 2.6

(Investigative) "A system just like our solar system exists in an atom." Comment on this statement.

Answer

The idea that an atom is like a mini solar system is helpful to explain atomic structure. Rutherford found a tiny central nucleus with the electrons in the large extra-nuclear portion, and Bohr's model has the electron revolving around the nucleus in specific paths called orbits or shells, just as planets revolve around the Sun.

How far it is true

  • As the Sun is at the centre of the solar system, the nucleus is at the centre of the atom and holds nearly all its mass (more than 99.9 %).
  • As planets revolve around the Sun, electrons revolve around the nucleus (Rutherford and Bohr models).
  • Both are mostly empty space.

Where it is wrong

  • Planets are held by gravity; electrons are held by the electrostatic attraction of opposite charges, and the nucleus by the strong nuclear force.
  • Planets can be at any distance; an electron can only be in fixed shells with fixed energies and is not allowed to occupy a space in between the orbits.
  • Electrons jump between energy levels, absorbing or emitting energy; planets do not.
  • A planet has a definite path, but according to the modern approach the electron is a charged cloud whose location cannot be predicted with one hundred percent certainty.
Conclusion

The solar-system picture is a helpful early model, but an atom is not really like a solar system.

Set B: More important long questions 6 questions

Long questions often set in board papers from this chapter, answered in the same full style.

Imp. LQ 1

How were cathode rays produced? What are their major characteristics?

Answer

Experiment

−cathode+anode (slit)high voltage+ plate− plateglow where the rays hitpath with no fieldcathode raysto vacuum pump (very low pressure)
Cathode rays bend towards the positive plate.

A discharge tube is a hard glass tube provided with two metallic electrodes and a vacuum pump to evacuate the gas present in it. When a very high voltage is applied to a gas at a very low pressure present in a glass tube, the glass surface behind the positive electrode started to glow, due to the rays emitted from the cathode. These rays were named cathode rays.

Characteristics of cathode rays

In 1897, British physicist Joseph John Thomson studied the properties of cathode rays by passing them through oppositely charged electric plates.

  1. Cathode rays bent towards the positively charged plate, showing that they carry negative charge.
  2. Thomson installed two magnets on either side of the discharge tube and noticed that cathode rays were also diverted by the magnetic field.
  3. Thomson used the findings of his experiments to calculate the mass to charge ratio of cathode rays, which finally proved that cathode rays are in fact negatively charged material particles.
  4. These particles were later named electrons. It was also shown that electrons are the subatomic particles of all elements.
Imp. LQ 2

Explain how canal rays were produced. How did they lead to the discovery of the proton?

Answer

Discovery

The presence of positively charged particles in an atom had been first observed by E. Goldstein in 1886. It was based on the concept that atoms are electrically neutral, having the same number of positive and negative charges.

Experiment

high voltage−++++++canal raysperforated cathode (−)anode (+)+ gas ions move towards the cathode · electrons (green) towards the anode
Goldstein's tube: positive canal rays pass through the holes of the perforated cathode.

He performed a series of experiments with a gas-discharge tube having a perforated cathode. A new type of rays were produced from the anode which moved towards the cathode. He called these new rays canal rays or anode rays.

Properties

  • The properties of these rays seemed to vary depending on the gas used in the discharge tube. In fact what he discovered was gas ions, and this also included hydrogen ions (H⁺). Goldstein at that time knew nothing about its significance.
  • They move towards the cathode, so they are positively charged.
  • They are heavy material particles: positive ions of the gas.

Discovery of the proton

In 1917, Rutherford performed experiments which proved that the hydrogen nucleus is present in other nuclei. Rutherford thought that a hydrogen nucleus or a proton must be the fundamental building block of all nuclei and also possibly a new fundamental particle as well.

Cathode raysCanal rays
from the cathodetowards the cathode
negativepositive
same for every gasdepend on the gas
very light (electrons)heavy (positive ions)
Imp. LQ 3

Describe the discovery of the neutron and the nucleus. What is the structure of an atom?

Answer

Discovery of the neutron

Later on, another particle, the neutron, was also discovered, which is known to carry no charge. The mass of a neutron is almost the same as that of a proton.

Check your book

The book gives the year as 1933. James Chadwick discovered the neutron in 1932.

These three particles, i.e. electron, proton and neutron, were given the name fundamental particles and are shown to be present in all atoms (except ordinary hydrogen, which does not have a neutron), irrespective of the fact that these atoms behave very differently from one another. However, the number of these particles is different in different atoms.

Discovery of the nucleus

After the discovery of these particles, a very important question arose: how are these particles arranged in a tiny place called the atom? Lord Rutherford, in 1911, provided the answer. He carried out a remarkable experiment in which he hit a stream of special type of particles (alpha particles) at a very thin gold foil.

lead blockα sourcegold foilmost pass straightthrougha few deflectedvery few bounce backzinc sulphide screen all round flashes where an α particle strikes
Rutherford's gold-foil experiment.
  • Most alpha particles passed straight through: the atom is mostly empty space.
  • A few were deflected and very few bounced back: there is a tiny, dense, positive centre.

Structure of the atom

From this experiment he concluded that an atom has two portions: a tiny central portion which he called the nucleus, and a relatively large area surrounding it, which he called the extra-nuclear portion. Almost all the mass of an atom is concentrated in the nucleus because both the heavy particles, protons and neutrons, are present here. In the nucleus these two particles are held together by a strong nuclear force. The electrons are in the extra-nuclear portion.

ParticleChargeMass
Electron−1.6022 × 10⁻¹⁹ C9.109 × 10⁻³¹ kg
Proton+1.6022 × 10⁻¹⁹ C1.673 × 10⁻²⁷ kg
Neutron0.01.675 × 10⁻²⁷ kg
Imp. LQ 4

Explain Bohr's atomic model. How are electrons distributed in shells and sub-shells?

Answer

Bohr's atomic model

In 1913, Niels Bohr proposed a model for the hydrogen atom which is called Bohr's atomic model.

  1. The electron can revolve around the nucleus of the atom in specific paths called orbits or shells.
  2. When the electron is revolving in one of these orbits, its energy is fixed.
  3. When the electron is present in the orbit which is closest to the nucleus, its energy is minimum and it is called the ground state of the atom.
  4. The orbits that are further away from the nucleus possess successively greater energy.
  5. The electron is not allowed to occupy a space in between the orbits.
+nucleusFirst shell (K)n = 1, E = E₁Second shell (L)n = 2, E = E₂Third shell (M)n = 3, E = E₃Fourth shell (N)n = 4, E = E₄E₄ > E₃ > E₂ > E₁the further the shell from the nucleus, the higher its energy
Shells K, L, M, N with E₄ > E₃ > E₂ > E₁.

Energy levels

Since the electron present in each shell has a fixed energy, these shells are also named energy levels. The shell nearest to the nucleus is called the first shell or K shell. The second shell is at a greater distance from the nucleus and the electron present in it possesses a greater value of energy. Similarly, electrons may also be present in the third or higher shells.

Distribution of electrons in shells: 2n² formula

To find out the number of electrons which can be accommodated in the shells, scientists devised the 2n² formula, where n = 1, 2, 3 … is the number of the shell.

ShellnMaximum electrons (2n²)
K12 × 1² = 2
L22 × 2² = 8
M32 × 3² = 18
N42 × 4² = 32

Sub-shells

Each shell is further sub-divided into sub-shells or orbitals. The number of sub-shells in a shell is equal to the value of n: the first shell has only the s sub-shell; the second has s and p; the third has s, p and d; the fourth has s, p, d and f. The maximum numbers of electrons in s, p, d and f sub-shells are 2, 6, 10 and 14. In the second shell, the 8 electrons are divided as 2 in s and 6 in p.

Modern approach

According to the modern approach, electrons are like charged clouds whose location around the nucleus cannot be predicted with one hundred percent certainty; there is only a certain probability of finding the electron at a certain distance from the nucleus.

Imp. LQ 5

What are isotopes? Explain the isotopes of hydrogen and carbon.

Answer

Definition

All the atoms of an element must necessarily have the same atomic number, but their mass number may vary depending upon the number of neutrons present in the nucleus. Atoms of the same element having different number of neutrons in their nuclei are called isotopes.

Properties of isotopes

Since the chemical properties of the elements are determined by the number of electrons, all isotopes show almost the same chemical behaviour, although their physical properties may be different.

Isotopes of hydrogen

Hydrogen exists as three isotopes, hydrogen, deuterium and tritium, represented by ¹₁H, ²₁H and ³₁H. Hydrogen (¹₁H) is the only atom which does not have a neutron. ²₁H has twice the mass of ¹₁H while the mass of ³₁H is thrice the mass of ¹₁H.

Isotopes of carbon

Element carbon has three isotopes as its atoms have six, seven and eight neutrons in their nuclei. These isotopes are represented as ¹²₆C, ¹³₆C and ¹⁴₆C. Similarly, the masses of the three isotopes of carbon are different.

Isotopes of hydrogenP=1Protium ¹₁HP=1N=1Deuterium ²₁HP=1N=2Tritium ³₁HIsotopes of carbonN=6P=6Carbon-12 ¹²₆CN=7P=6Carbon-13 ¹³₆CN=8P=6Carbon-14 ¹⁴₆C
Isotopes of hydrogen and of carbon.
IsotopeProtonsNeutronsNote
¹₁H (protium)10only atom with no neutron
²₁H (deuterium)11twice the mass of ¹H
³₁H (tritium)12radioactive
¹²₆C66atomic-mass standard
¹³₆C67stable
¹⁴₆C68radioactive; carbon dating
Imp. LQ 6

Define relative atomic mass. How is it calculated from isotopic abundances? Give examples.

Answer

Need for relative atomic masses

Ever since the existence of the atom was recognised, chemists were trying to find a method to compare the masses of different atoms. Without knowing the relative masses of atoms, we would not know in which ratio of masses we mix the reactants to carry out a chemical reaction.

The carbon-12 scale

In 1961, chemists adopted a new scale. The unit mass on this scale is 1/12 of the mass of the light isotope of carbon taken as 12. The mass of one atom of carbon on this scale is exactly 12 and the masses of the other atoms are measured relative to this unit.

Definition
Relative atomic mass

The mass of an atom of an element relative to the mass of the light isotope of carbon taken as 12.

Definition
Atomic mass unit (amu)

One-twelfth the mass of an atom of carbon-12. Example: hydrogen-1 is 1.007 amu; sulphur-32 is 31.972 amu.

Calculation from isotopic abundance

An element usually consists of a few different isotopes with different mass numbers, called relative isotopic masses. Each isotope has its own naturally occurring abundance, called isotopic abundance. The relative atomic mass is calculated from the relative isotopic masses (m) and isotopic abundances (p):

Relative atomic mass = (m₁p₁ + m₂p₂ + m₃p₃ + …) ÷ 100

Example 1: krypton

Worked example⁸⁰Kr 2.0 %, ⁸²Kr 12.0 %, ⁸³Kr 12.0 %, ⁸⁴Kr 57.0 %, ⁸⁵Kr 17.0 %
  1. (80 × 2.0 + 82 × 12.0 + 83 × 12.0 + 84 × 57.0 + 85 × 17.0) ÷ 100 = 8373 ÷ 100

Answer83.7

Check your book

The book's working prints "85 × 57.0" for the last term; the table gives 17.0 %, and only 17.0 gives 83.7.

Example 2: light isotope of chlorine

Worked exampleRAM of Cl = 35.45; Cl-37 24.23 %; light isotope 75.77 %
  1. 35.45 = (Cl × 75.77 + 37 × 24.23) ÷ 100
  2. 3545 − 896.51 = Cl × 75.77, so Cl = 2648.49 ÷ 75.77

Answer34.95

Example 3: lead

Worked example²⁰⁴Pb 2.0 %, ²⁰⁶Pb 24.0 %, ²⁰⁷Pb 22.0 %, ²⁰⁸Pb 52.0 %
  1. (204 × 2 + 206 × 24 + 207 × 22 + 208 × 52) ÷ 100 = 20 722 ÷ 100

Answer207.2

End of Chapter 2 Long QuestionsNext: Chapter 2 Numericals →
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Full guide: Atomic Structure (notes, diagrams, all questions, self-test)
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