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9th Class Physics · Punjab Board · Complete learning guide

Chapter 1Physical Quantities and Measurements

Every topic, every MCQ and every exercise question, explained step by step in simple language. Written for the Punjab Board new-syllabus Physics book, English medium.

On their own page:Chapter 1 MCQsChapter 1 Short QuestionsChapter 1 Long QuestionsChapter 1 Numericals

  1. Read Part 1 slowly. Do the worked examples yourself on paper, then compare.
  2. Try each MCQ before opening its answer, then read why the wrong options are wrong.
  3. Learn the short answers in your own words, then do the numericals without looking.
  4. Finish with the self-test in Part 7. A wrong answer tells you which topic to read again.
Part 1of 7

Learn the Chapter

Read this first. Everything in the exercises comes from these topics.

  1. 1What physics is and why we measure
  2. 2Physical quantities and measurement
  3. 3Base and derived quantities
  4. 4Prefixes
  5. 5Scientific notation (standard form)
  6. 6Measuring length
  7. 7Vernier Callipers
  8. 8Micrometer screw gauge
  9. 9Measuring mass
  10. 10Measuring time
  11. 11Measuring volume
  12. 12Errors in measurement
  13. 13Significant figures
  14. 14Precision and accuracy
Topic 1

What physics is and why we measure

Definition
Physics

The branch of science that studies matter, energy and how they act on each other.

Physics explains why a ball falls, how a phone sends a message, and how a hospital scanner sees inside the body. It depends on measurement: saying "this table is long" is only an opinion, but "this table is 1.5 m long" is a fact anyone can check.

Main branches of physics

BranchWhat it studies
MechanicsMotion and forces
Heat (thermodynamics)Heat, temperature and energy transfer
Sound (acoustics)Sound waves
Light (optics)How light behaves, as in lenses and mirrors
Electricity and magnetismElectric charges, currents and magnets
Atomic and nuclear physicsAtoms and the centre of atoms (the nucleus)
Topic 2

Physical quantities and measurement

Definition
Physical quantity

Anything we can measure with an instrument and write as a number with a unit. Examples: length, mass, time, temperature.

Definition
Non-physical quantity

Something with no instrument or standard unit, so it cannot be measured. Examples: love, beauty, honesty, trust. Colour, as a person sees it, is treated as non-physical in your book because it depends on who is looking.

Definition
Measurement

Comparing an unknown quantity with a fixed standard, called a unit.

Every measurement has two parts: a number (magnitude) and a unit.

MeasurementNumber (magnitude)Unit
5 m5metre (m)
250 g250gram (g)
30 s30second (s)
Remember

A number without a unit means nothing. "The rod is 5 long" does not tell us if it is 5 mm or 5 km. Always write the unit.

Why do we need standard units?

Long ago people measured with hand spans and footsteps, but every hand and foot is different. A standard unit means the same thing everywhere, so a shopkeeper, a tailor, an engineer and a scientist in any country all get the same result.

Topic 3

Base and derived quantities

Definition
Base quantities

The seven quantities that stand on their own and are not made from other quantities. Each has an SI base unit (SI = International System of Units).

Base quantitySI base unitSymbol
Lengthmetrem
Masskilogramkg
Timeseconds
Electric currentampereA
TemperaturekelvinK
Amount of substancemolemol
Luminous intensity (brightness of light)candelacd
Exam tip

Learn these seven by heart; they come up again and again in MCQs. The kilogram is the only base unit that already has a prefix (kilo) in its name.

Definition
Derived quantities

Quantities made by multiplying or dividing base quantities. Their units are derived units.

Derived quantityHow it is madeSI unitIn base units
Arealength × breadthsquare metrem²
Volumelength × breadth × heightcubic metrem³
Speeddistance ÷ timemetre per secondm s⁻¹
Densitymass ÷ volumekilogram per cubic metrekg m⁻³
Accelerationchange in speed ÷ timemetre per second squaredm s⁻²
Forcemass × accelerationnewton (N)kg m s⁻²
Pressureforce ÷ areapascal (Pa)kg m⁻¹ s⁻²
Work, energyforce × distancejoule (J)kg m² s⁻²
Powerwork ÷ timewatt (W)kg m² s⁻³
Electric chargecurrent × timecoulomb (C)A s
Worked exampleWhat is the newton in base units?
  1. Force = mass × acceleration.
  2. Unit of mass = kg, and unit of acceleration = m s⁻².
  3. So the unit of force = kg × m s⁻² = kg m s⁻². This unit is named the newton.
Remember

Derived units come only from multiplying or dividing base units. We never add or subtract them.

Rules for writing SI units
  • Use the correct symbol, not a short form: write s, not sec.
  • Symbols have no plural: write 10 kg, not 10 kgs.
  • Unit names start with a small letter, even if named after a person (newton, kelvin); the symbol takes a capital (N, K).
  • Leave a space between the number and the unit: 5 m, not 5m.
  • Leave a space between two unit symbols: N m. ("mN" would mean millinewton.)
  • Use only one prefix at a time: write 7 ps, not 7 µµs.
Topic 4

Prefixes

Definition
Prefix

A word placed before a unit to show a power of ten, so very large or very small numbers are easy to read. 5000 m becomes 5 km.

Multiples make a unit bigger; sub-multiples make it smaller.

PrefixSymbolValueExample
exaE10¹⁸1 Em = 10¹⁸ m
petaP10¹⁵1 Pm = 10¹⁵ m
teraT10¹²1 TB = 10¹² bytes
gigaG10⁹1 GHz = 10⁹ Hz
megaM10⁶1 MW = 10⁶ W
kilok10³1 km = 1000 m
hectoh10²1 hPa = 100 Pa
decada10¹1 dam = 10 m
decid10⁻¹1 dm = 0.1 m
centic10⁻²1 cm = 0.01 m
millim10⁻³1 mm = 0.001 m
microµ10⁻⁶1 µm = 0.000001 m
nanon10⁻⁹1 ns = 10⁻⁹ s
picop10⁻¹²1 pm = 10⁻¹² m
femtof10⁻¹⁵1 fm = 10⁻¹⁵ m
attoa10⁻¹⁸1 as = 10⁻¹⁸ s
kmmcmmm× 1000÷ 1000× 100÷ 100× 10÷ 10
Going to a smaller unit, multiply (the number gets bigger). Going to a larger unit, divide (the number gets smaller).
Worked exampleConvert 2.5 km into cm
  1. km to m: 2.5 × 1000 = 2500 m.
  2. m to cm: 2500 × 100 = 250 000 cm.

Answer2.5 km = 250 000 cm = 2.5 × 10⁵ cm

Worked exampleConvert 450 mg into g
  1. milli means 10⁻³, so 1 mg = 0.001 g.
  2. 450 × 0.001 = 0.45 g.

Answer450 mg = 0.45 g

Exam tip

Capital and small letters matter. m is milli and M is mega, so 1 mW and 1 MW are a billion times apart. And 5 pm in physics means 5 picometres, not 5 o'clock!

Topic 5

Scientific notation (standard form)

Definition
Scientific notation

Writing a number as N × 10ⁿ, where N is from 1 up to (but not including) 10 and the power n is a whole number.

N × 10ⁿ
1 ≤ N < 10, and n is a whole number
How to change a number into scientific notation
  1. Move the decimal point until only one non-zero digit is left before it.
  2. Count the places you moved it. That is n.
  3. Moved left (a big number): n is positive. Moved right (a small number): n is negative.
NumberMovesScientific notation
6400 km3 places left6.4 × 10³ km
300 000 000 m s⁻¹8 places left3.0 × 10⁸ m s⁻¹
0.00556 m3 places right5.56 × 10⁻³ m
0.000000042 s8 places right4.2 × 10⁻⁸ s
206.4 × 10² m2 places left, so add 2 to the power2.064 × 10⁴ m

Calculating with powers of ten

OperationRuleExample
MultiplyMultiply the numbers, add the powers(2 × 10³) × (3 × 10⁴) = 6 × 10⁷
DivideDivide the numbers, subtract the powers(8 × 10⁶) ÷ (2 × 10²) = 4 × 10⁴
Add or subtractFirst make the powers the same4 × 10⁻⁴ + 3 × 10⁻⁵ = 4 × 10⁻⁴ + 0.3 × 10⁻⁴ = 4.3 × 10⁻⁴
Topic 6

Measuring length

Definition
Least count (LC)

The smallest length an instrument can read correctly. A smaller least count means a more precise instrument.

InstrumentRange (about)Least countGood for
Measuring tapeup to several metres1 mmRoom, cloth, a field
Metre ruleup to 1 m1 mmTable, book, rod
Vernier Callipersup to about 15 cm0.1 mm = 0.01 cmPipe, test tube, coin, small depth
Micrometer screw gaugeup to about 2.5 cm0.01 mm = 0.001 cmThin wire, thin sheet
Definition
Parallax error

The error when a scale is read from the side, so the mark seems to shift. Keep your eye straight above the mark and the object close to the scale.

0123456789101112131415objectA: reads too muchB: correctC: reads too little
Eye B looks straight down at the end of the object, so it gets the true reading. Eyes A and C read a wrong mark.

If the end of the rule is worn out

worn12345678910111213pencil: starts at 2.0 cm, ends at 9.5 cm
Start from a clear mark and subtract: length = 9.5 cm − 2.0 cm = 7.5 cm.
Topic 7

Vernier Callipers

Vernier Callipers measure small lengths, to 0.1 mm. They have a fixed main scale and a sliding vernier scale, and are named after Pierre Vernier, who invented this kind of scale.

OutsidejawsInside jawsLock screwMain scaleVernier scale (slides)Depth rod
Outside jaws measure outer size. Inside jaws measure inner size. The depth rod measures depth.

How the least count comes out

  1. One small main scale division (MSD) = 1 mm.
  2. 10 vernier divisions cover 9 mm, so 1 vernier division (VSD) = 0.9 mm.
  3. Least count (vernier constant) = 1 MSD − 1 VSD = 1 mm − 0.9 mm = 0.1 mm = 0.01 cm.
LC = 1 MSD ÷ number of vernier divisions
Short way: 1 mm ÷ 10 = 0.1 mm
How to take a reading
  1. Close the jaws and check for zero error.
  2. Hold the object gently between the jaws.
  3. Main scale reading (MSR): read the main scale mark just before the vernier's zero.
  4. Vernier reading: find the vernier line that lines up exactly with a main scale line. Call its number n.
Reading = MSR + (n × LC)
23main scale (cm)05710vernier scale: 10 divisions = 9 mm↑ zero just past 2.3
Vernier zero is just past 2.3 cm, so MSR = 2.3 cm. The 7th vernier line lines up with a main scale line.
Worked exampleReading from the diagram
  1. MSR = 2.3 cm, n = 7, LC = 0.01 cm.
  2. Reading = 2.3 cm + (7 × 0.01 cm) = 2.3 cm + 0.07 cm.

Answer2.37 cm

Definition
Zero error

When the jaws are fully closed the two zeros should line up exactly. If they do not, every reading is off by the same amount.

TypeWhat you seeExampleZero error
PositiveVernier zero is to the right of the main zero4th vernier line lines up+ (4 × 0.01 cm) = +0.04 cm
NegativeVernier zero is to the left of the main zero7th vernier line lines up− (10 − 7) × 0.01 cm = −0.03 cm
Corrected reading = observed reading − zero error
Keep the sign of the error
CaseObserved readingZero errorCorrected reading
Positive error2.37 cm+0.04 cm2.37 − 0.04 = 2.33 cm
Negative error2.37 cm−0.03 cm2.37 − (−0.03) = 2.40 cm
Topic 8

Micrometer screw gauge

The screw gauge measures even smaller lengths, to 0.01 mm: the diameter of a thin wire or the thickness of a thin sheet.

object goes hereAnvilSpindleSleeve: main scale + datum lineThimble: circular scaleRatchetU-shaped frame
Turn only the ratchet once the object is touching. It stops you squeezing too hard, which would damage the object and give a wrong reading.
Definition
Pitch

The distance the spindle moves in one full turn of the thimble.

Least count = pitch ÷ number of divisions on the circular scale
PitchCircular scale divisionsLeast count
1 mm1001 ÷ 100 = 0.01 mm
0.5 mm500.5 ÷ 50 = 0.01 mm
How to take a reading
  1. Close the gauge and check for zero error.
  2. Place the object between the anvil and spindle. Turn the ratchet until it clicks.
  3. Main scale reading (MSR): read the last mark visible on the sleeve.
  4. Circular scale reading (CSR): find the thimble line that meets the datum line.
Reading = MSR + (CSR × LC)
0123sleeve: main scale (mm), datum line657075← on datum linethimble: circular scale
Last visible mark is 3 mm. Line 70 meets the datum line. The least count is 0.01 mm.
Worked exampleReading from the diagram
  1. MSR = 3 mm, CSR = 70, LC = 0.01 mm.
  2. Reading = 3 mm + (70 × 0.01 mm) = 3 mm + 0.70 mm.

Answer3.70 mm

Zero error in a screw gauge

What you seeTypeExampleZero error
Circular zero is below the datum linePositiveLine 3 meets the datum line+ (3 × 0.01) = +0.03 mm
Circular zero is above the datum lineNegativeLine 97 meets the datum line− (100 − 97) × 0.01 = −0.03 mm

Use the same rule as before: corrected reading = observed reading − zero error.

Topic 9

Measuring mass

Definition
Mass

The amount of matter in an object. Its SI unit is the kilogram, and it is measured with a balance.

BalanceHow it works
Beam balanceCompares the object with known masses on the other side of a beam.
Physical balanceA more sensitive beam balance used in a laboratory.
Electronic balanceShows the mass on a screen. It is quick and easy.
Exam tip

Before using any balance, make sure it reads zero when empty. An electronic balance has a "tare" button that sets it to zero. If you skip this, you get a systematic error.

Topic 10

Measuring time

The SI unit of time is the second. A stopwatch measures short time intervals.

Mechanical stopwatchDigital stopwatch
Works bySpring and gearsElectronic circuit
DisplayHands on a dialNumbers on a screen
Least count (typical)0.1 s0.01 s
PowerWound by handBattery

Time standards come from things that repeat regularly: the Earth spinning once a day, the Earth going round the Sun once a year, and the phases of the Moon. Today the second is defined using vibrations of the caesium-133 atom, because they are extremely regular.

Remember

Your reaction time is about 0.2 s, so a hand-held stopwatch is never perfectly exact, even if it shows 0.01 s. Take several readings and find the average.

Topic 11

Measuring volume

Definition
Volume

The space an object takes up. A measuring cylinder measures the volume of a liquid.

1 mL = 1 cm³ and 1 L = 1000 mL = 1000 cm³
Definition
Meniscus

The curved surface of a liquid in a narrow tube. Read water at the bottom of the curve; mercury curves up, so read the top of its curve.

Eye too high: reads too muchEye level with the bottomEye too low: reads too littleRead here: the lowestpoint of the meniscus
Keep your eye level with the bottom of the curve. An eye too high reads too much; an eye too low reads too little.
Precautions
  • Place the cylinder on a flat, level surface.
  • Keep your eye level with the meniscus.
  • Choose a cylinder that suits the amount of liquid. A narrow one gives a clearer reading.
  • Handle it with care, as it is usually made of glass.

Volume of an irregular solid (a stone)

Method 1: measuring cylinderV₁ = 50 mLbeforeV₂ = 75 mLstone insideMethod 2: displacement cancan filled to the spoutcollect water
Method 1: the rise in water level gives the volume. Method 2: the water pushed out of a displacement can gives the volume.
Worked exampleMeasuring cylinder method
  1. Note the water level: V₁ = 50 mL.
  2. Tie the stone with a thread, lower it in gently, and note the new level: V₂ = 75 mL.
  3. Volume of stone = V₂ − V₁ = 75 mL − 50 mL.

Answer25 mL = 25 cm³

Displacement can: fill the can to the spout, lower the stone in and collect the water that flows out. Its volume equals the volume of the stone. This is useful when the stone is too big for the cylinder.

Topic 12

Errors in measurement

Definition
Error

The difference between the measured value and the true value. No measurement is perfect.

TypeWhat it isCausesHow to reduce it
Human errorMistake by the person measuringMisreading a scale, writing a wrong value, slow reactionTake care, repeat the reading
Systematic errorThe same error in every reading, all in one directionZero error, poor calibration, wrong markingsCheck and correct the instrument, compare with a better one
Random errorReadings differ slightly each timeChanges in temperature, air current, small changes in how it is doneTake many readings and find the average
Worked exampleReducing random error with an average
  1. A pen is measured three times: 11.0 cm, 11.1 cm and 11.2 cm.
  2. Add them: 11.0 + 11.1 + 11.2 = 33.3 cm.
  3. Divide by the number of readings: 33.3 ÷ 3.

Answer11.1 cm

Topic 13

Significant figures

Definition
Significant figures

The digits in a measurement we can trust: all the certain digits plus the first doubtful digit. They show how carefully something was measured.

RuleExampleCount
All non-zero digits count2.473
Zeros between non-zero digits count2.0474
Zeros at the start do not count0.00452
Zeros at the end, after a decimal point count3.403
In scientific notation, count only the digits before ×3.420 × 10⁴4
Remember

A number like 5000 is unclear: are the zeros real, or do they only hold places? Write 5 × 10³ (1 significant figure) or 5.00 × 10³ (3 significant figures).

Rounding off
  • Next digit less than 5: keep the last digit as it is. 4.32 becomes 4.3.
  • Next digit more than 5: raise the last digit by 1. 4.37 becomes 4.4.
  • Next digit exactly 5: raise it if the last digit is odd (4.35 becomes 4.4), keep it if even (4.25 becomes 4.2). Some teachers always round 5 up, so ask yours.
OperationRuleExample
Add or subtractKeep the fewest decimal places of any number12.321 − 10.3 = 2.021, written as 2.0
Multiply or divideKeep the fewest significant figures of any number2.5 × 1.23 = 3.075, written as 3.1
Topic 14

Precision and accuracy

Definition
Precision

How close repeated readings are to each other. It depends on the instrument: a smaller least count gives more precision.

Definition
Accuracy

How close a reading is to the true value. It depends on careful work, a correct instrument and more significant figures.

PrecisionAccuracy
MeaningHow close repeated readings are to each otherHow close a reading is to the true value
Depends onThe instrument: a smaller least countCareful work, a correct instrument, more significant figures
Example (true value 100)99.9, 100.1, 100.2 are close together98, 101, 102 are all near 100
Precise and accuratePrecise, not accurateAccurate, not preciseNeither
Think of each dot as a reading, and the centre as the true value.
Exam tip

A clock that always runs exactly 5 minutes fast is precise (it is steady) but not accurate (it is wrong).

Part 2of 7

MCQs Fully Solved

Try each one first: tap an option to check it, then read the reasoning and why the others are wrong.

Only the mcqs on one page →
A note about the questions

The wording follows published solved exercises and every answer was re-checked by hand, so the wording or the order of options may differ slightly from your print.

Answered 0 of 24 · Correct 0

Set A: Textbook exercise 11 MCQs

The multiple-choice questions at the end of Chapter 1 in your book, in the book's option order.

Q1.1Vernier Callipers and Screw Gauge

The instrument that is most suitable for measuring the thickness of a few sheets of cardboard is:

Q1.2Prefixes and Scientific Notation

One femtometre is equal to:

Q1.3Prefixes and Scientific Notation

A light year is a unit of:

Q1.4Physical Quantities and SI Units

Which one is a non-physical quantity?

Q1.5Measuring Volume

When using a measuring cylinder, one precaution to take is to:

Q1.6Measuring Volume

Volume of water consumed by you per day is estimated in:

Q1.7Measuring Volume

A displacement can is used to measure:

Q1.8Significant Figures

Two rods with lengths 12.321 cm and 10.3 cm are placed side by side. The difference in their lengths is:

Q1.9Vernier Callipers and Screw Gauge

Four students measure the diameter of a cylinder with Vernier Callipers. Which of the following readings is correct?

Q1.10Prefixes and Scientific Notation

Which of the following measures is likely to represent the thickness of a sheet of this book?

Q1.11Vernier Callipers and Screw Gauge

In a Vernier Callipers, ten smallest divisions of the Vernier scale are equal to nine smallest divisions of the main scale. If the smallest division of the main scale is half a millimetre, the Vernier constant is equal to:

Set B: More MCQs from this chapter 13 MCQs

Extra questions on the same ideas, of the kind set in board papers and class tests.

QB1Physical Quantities and SI Units

Which one of the following units is not a derived unit?

QB2Physical Quantities and SI Units

Amount of a substance in terms of numbers is measured in:

QB3Significant Figures

The number of significant figures in 0.00650 s is:

QB4Significant Figures

Which of the following numbers shows 4 significant digits?

QB5Prefixes and Scientific Notation

Which of the following prefixes represents the largest value?

QB6Vernier Callipers and Screw Gauge

A micrometer can be used to measure:

QB7Vernier Callipers and Screw Gauge

The instrument that best measures the internal diameter of a pipe is:

QB8Vernier Callipers and Screw Gauge

The least count of a screw gauge is 0.01 mm. If the main scale reading is zero and the third line of its circular scale coincides with the datum line, the measurement is:

QB9Prefixes and Scientific Notation

9.483 × 10³ m is the standard form of:

QB10Physical Quantities and SI Units

Which of the following is a base unit?

QB11Significant Figures

The number having one significant digit is:

QB12Prefixes and Scientific Notation

The ratio of millimetre to micrometre is:

QB13Prefixes and Scientific Notation

0.2 mm in units of metres is:

Part 3of 7

Short Questions

Exam-ready answers. Learn the meaning, then write them in your own words.

Only the short questions on one page →
Short Q 1.1

Can a non-physical quantity be measured? If yes, then how?

Answer

No. A non-physical quantity cannot be measured with an instrument, because it has no standard unit. Examples are love, beauty, honesty and trust.

We can only judge such things in other ways, like a survey with ratings out of 10. These give an opinion score, not a physical measurement.

Short Q 1.2

What is measurement? Name its two parts.

Answer

Measurement is the process of comparing an unknown quantity with a known standard quantity (a unit).

Its two parts are (1) a number (magnitude) and (2) a unit. In 5 m, the number is 5 and the unit is metre.

Short Q 1.3

Why do we need a standard unit for measurement?

Answer

A standard unit means the same everywhere. It makes trade fair, keeps work accurate, and lets people everywhere share and compare results.

Short Q 1.4

Write the names of 3 base quantities and 3 derived quantities.

Answer
Base quantitiesDerived quantities
LengthArea
MassVolume
TimeSpeed
Short Q 1.5

Which SI unit will you use to express the height of your desk?

Answer

The metre (m), since it is the SI unit of length. A desk is about 0.75 m high; in everyday use we may also write this as 75 cm.

Short Q 1.6

Write the names and symbols of all SI base units.

Answer
UnitSymbolMeasures
metremlength
kilogramkgmass
secondstime
ampereAelectric current
kelvinKtemperature
molemolamount of substance
candelacdluminous intensity
Short Q 1.7

Why is a prefix used? Name three sub-multiple and three multiple prefixes with their symbols.

Answer

Prefixes make very large and very small numbers short and easy to read and write. For example, 5000 m can be written as 5 km.

Sub-multiplesMultiples
milli (m) = 10⁻³kilo (k) = 10³
micro (µ) = 10⁻⁶mega (M) = 10⁶
nano (n) = 10⁻⁹giga (G) = 10⁹
Short Q 1.8

What is meant by: (a) 5 pm (b) 15 ns (c) 6 µm (d) 5 fs?

Answer
WrittenMeaningValue
(a) 5 pm5 picometres5 × 10⁻¹² m
(b) 15 ns15 nanoseconds15 × 10⁻⁹ s = 1.5 × 10⁻⁸ s
(c) 6 µm6 micrometres6 × 10⁻⁶ m
(d) 5 fs5 femtoseconds5 × 10⁻¹⁵ s
Watch out

Look at the last letter: m means metre and s means second. Some keys write (d) in metres, which is wrong.

Short Q 1.9

(a) For what purpose are Vernier Callipers used? (b) Name their two main parts. (c) How is the least count found? (d) What is meant by zero error?

Answer

(a) To measure small lengths precisely, to 0.1 mm, such as the diameter of a pipe, the inner size of a test tube, or a small depth.

(b) The main scale and the vernier scale.

(c) Least count = 1 main scale division − 1 vernier division = 1 mm − 0.9 mm = 0.1 mm.

(d) When the jaws are closed, the zeros of the two scales should line up. If they do not, the instrument has a zero error.

Short Q 1.10

State the least count and vernier scale reading as shown in the figure and hence find the length.

Answer

Least count = 1 mm ÷ 10 = 0.1 mm = 0.01 cm.

Length = MSR + (vernier line number × LC)

For a main scale reading of 2.6 cm with the 4th vernier line lining up: length = 2.6 + (4 × 0.01) = 2.64 cm.

Check your book

Solved keys disagree on this figure. One reads the 4th vernier line (2.64 cm), another the 5th (2.65 cm). Find which vernier line lines up in your book's figure and use that number in the same formula.

Short Q 1.11

Which reading out of A, B and C shows the correct length and why?

Answer

B is correct, because the eye is straight above the mark (at a right angle to the scale). A and C read from the side, so they have parallax error.

0123456789101112131415objectA: reads too muchB: correctC: reads too little
The same idea as the figure in your book: only the eye straight above the mark reads correctly.
Part 4of 7

Constructed Response Questions

These test whether you really understand. Give a reason every time.

CRQ 1.1

In which unit will you express each of the following?

Answer
QuantityBest unit
(a) Thickness of a five-rupee coinmillimetre (mm)
(b) Length of a bookcentimetre (cm)
(c) Length of a football fieldmetre (m)
(d) Distance between two citieskilometre (km)
(e) Mass of a five-rupee coingram (g)
(f) Mass of a school bagkilogram (kg)
(g) Duration of a class periodminute (min)
(h) Volume of petrol in a car tanklitre (L)
(i) Time to boil one litre of milkminute (min)
The idea

Pick the unit that gives a small, easy number.

CRQ 1.2

Why might a standard system of measurement be helpful to a tailor?

Answer

With standard units, the tailor can take a customer's size in inches or centimetres and cut the cloth exactly. Measurements can also be shared with other tailors or written down for later, and they will mean the same thing.

CRQ 1.3

A micrometer screw gauge has a minimum main scale reading of 1 mm and 100 divisions on its circular scale. One turn of the thimble moves 1 mm on the main scale. What is the least count? From the figure, what is the thickness of the steel rod?

Answer
Worked exampleSolution
  1. Least count = pitch ÷ divisions = 1 mm ÷ 100 = 0.01 mm (= 0.001 cm).
  2. From the figure: main scale reading = 3 mm, and circular scale reading = 70.
  3. Thickness = 3 mm + (70 × 0.01 mm) = 3 mm + 0.70 mm.

Answer3.70 mm

Check your book

These readings match the screw gauge diagram in Part 1. Compare them with your book's figure.

CRQ 1.4

You are given a metre scale and a bundle of pencils. How can you measure the diameter of a pencil with the same precision as Vernier Callipers?

Answer
Worked exampleMethod
  1. Place 10 identical pencils side by side, touching each other with no gaps.
  2. Measure the total width with the metre scale. Suppose it is 7.5 cm.
  3. Divide by 10: diameter = 7.5 cm ÷ 10.

Answer0.75 cm

Why this works: the scale reads to 1 mm. Dividing by 10 shares that 1 mm among 10 pencils, so the precision becomes 1 mm ÷ 10 = 0.1 mm, the same as Vernier Callipers.

CRQ 1.5

The end of a metre scale is worn out. Where will you place a pencil to find its length?

Answer

Do not start from the worn end. Place one end of the pencil at a clear mark, such as 2.0 cm. Read the other end, say 9.5 cm. Then subtract: length = 9.5 − 2.0 = 7.5 cm.

worn12345678910111213pencil: starts at 2.0 cm, ends at 9.5 cm
Start from a clear mark and subtract.
CRQ 1.6

Why is it better to place the object close to the metre scale?

Answer

If the object is far from the scale, the mark appears to shift when you look from a slight angle. This is parallax error. Keeping the object touching the scale makes the reading much more exact.

CRQ 1.7

Why is a standard unit needed to measure a quantity correctly?

Answer

Without a standard, one person's "one hand span" would differ from another's. A standard unit is fixed and the same for everyone, so measurements can be trusted and compared.

CRQ 1.8

Suggest some natural phenomena that could serve as a reasonably accurate time standard.

Answer
  • Earth spinning on its axis (one day)
  • Earth going round the Sun (one year)
  • Phases of the Moon (about one month)
  • Vibrations of atoms such as caesium-133 (used by atomic clocks)
CRQ 1.9

It is difficult to locate the meniscus in a wider vessel. Why?

Answer

In a wide vessel the liquid surface is almost flat and only curves near the edge, so there is no clear lowest point to read. A narrow cylinder gives a clear curve.

CRQ 1.10

Which instrument can be used to measure: (i) the internal diameter of a test tube (ii) the depth of a beaker?

Answer

Vernier Callipers can do both: (i) with the inside jaws, and (ii) with the depth rod.

Part 5of 7

Comprehensive (Long) Questions

Long answers, explained in full with headings. Learn the structure: definition, explanation, diagram or table, example.

Only the long questions on one page →

Set A: Textbook comprehensive questions 5 questions

The long questions at the end of the chapter in your book.

Long Q 1.1

What is meant by base and derived quantities? Give the names and symbols of SI base units.

Answer

Base quantities

Definition
Base quantities

The independent physical quantities on which all other quantities are built. They cannot be described in terms of any other quantity.

Scientists chose seven base quantities. Length, mass and time are the three we meet most often in this book.

Derived quantities

Definition
Derived quantities

Quantities that are described by multiplying or dividing base quantities.

Examples: speed = distance ÷ time; area = length × breadth; density = mass ÷ volume. Their units (m s⁻¹, m², kg m⁻³) are called derived units.

The seven SI base quantities and units

Base quantitySI base unitSymbol
Lengthmetrem
Masskilogramkg
Timeseconds
Electric currentampereA
TemperaturekelvinK
Amount of substancemolemol
Luminous intensity (brightness of light)candelacd
Key point

Every other quantity in physics, from force to electric charge, can be built from these seven.

Long Q 1.2

Give three examples of derived units in SI. How are they derived from base units?

Answer

What a derived unit is

A derived unit is the unit of a derived quantity. It is obtained by multiplying or dividing the SI base units in the same way the quantity itself is defined.

Three examples

Derived quantityDefinitionHow the unit is derivedDerived unit
Arealength × breadthm × msquare metre (m²)
Volumelength × breadth × heightm × m × mcubic metre (m³)
Speeddistance ÷ timem ÷ smetre per second (m s⁻¹)

A unit with its own name

Worked exampleThe newton (unit of force)
  1. Force = mass × acceleration.
  2. Unit = kg × m s⁻² = kg m s⁻².
  3. This combination is given the special name newton (N).
Conclusion

Derived units come only from multiplying or dividing base units, never from adding or subtracting them.

Long Q 1.3

State the similarities and differences between Vernier Callipers and a micrometer screw gauge.

Answer

Similarities

  • Both measure small lengths more precisely than a metre rule.
  • Both have a main scale and a second, finer scale.
  • Both can have a zero error, which must be found and corrected before use.
  • Both give the reading as: main scale reading + (lined-up division × least count).

Differences

PointVernier CallipersMicrometer screw gauge
Least count0.1 mm (0.01 cm)0.01 mm (0.001 cm)
PrecisionLess precise10 times more precise
Second scaleSliding vernier scaleRotating circular scale on the thimble
Holds the object withJawsAnvil and spindle
Can measureOuter size, inner size and depthOnly outer size (thickness, diameter)
Range (about)Up to about 15 cmUp to about 2.5 cm
Typical useDiameter of a pipe, depth of a beakerDiameter of a wire, thickness of a sheet
Which one to use

Choose the Vernier Callipers for something a few millimetres to a few centimetres across, and the screw gauge for something less than a millimetre thick.

Long Q 1.4

Identify and explain the reasons for human errors, random errors and systematic errors in experiments.

Answer

What an error is

An error is the difference between a measured value and the true value. Every measurement has some error; the aim is to make it as small as possible.

1. Human errors

These are mistakes made by the person taking the measurement.

Reasons
  • Reading a scale at an angle (parallax error).
  • Writing down a wrong value or unit.
  • Slow reaction when starting or stopping a stopwatch.
How to reduce them
  • Take care and repeat each reading.
  • Keep the eye at right angles to the scale.
  • Use digital or automatic instruments where possible.

2. Systematic errors

These push every reading off by the same amount in the same direction, so repeating the reading does not help.

Reasons
  • Zero error in the instrument.
  • Poor calibration or wrong markings on the scale.
  • A fault in the way the apparatus is set up.
How to reduce them
  • Check the zero before measuring and correct for it.
  • Compare the instrument with a more accurate one.
  • Apply a correction factor to the readings.

3. Random errors

These make repeated readings of the same quantity come out slightly different each time, in no fixed pattern.

Reasons
  • Small changes in temperature, air currents or voltage.
  • Small differences in how each reading is taken.
How to reduce them
  • Take many readings and find their average.
  • Time many swings of a pendulum (say 20) and divide, instead of timing one.
Worked exampleReducing random error
  1. Readings: 11.0 cm, 11.1 cm, 11.2 cm.
  2. Average = (11.0 + 11.1 + 11.2) ÷ 3 = 33.3 ÷ 3.

Answer11.1 cm

TypeEffectMain cure
HumanCareless or misread valuesCare, repetition, digital instruments
SystematicAll readings off the same wayCheck and correct the instrument
RandomReadings scatterAverage many readings
Long Q 1.5

Differentiate between precision and accuracy of a measurement with examples.

Answer

Precision

Definition
Precision

How close repeated measurements of the same quantity are to each other.

Precision depends on the instrument: the smaller its least count, the more precise the reading. A screw gauge (0.01 mm) is more precise than a metre rule (1 mm).

Accuracy

Definition
Accuracy

How close a measurement is to the true (accepted) value.

Accuracy depends on careful work, a correctly calibrated instrument with no zero error, and recording enough significant figures.

Examples

ReadingsTrue valueResult
99.9, 100.1, 100.290Precise (close together) but not accurate (far from the true value)
98, 101, 102100Accurate (close to the true value) but less precise (spread out)
99.9, 100.1, 100.2100Both precise and accurate
Precise and accuratePrecise, not accurateAccurate, not preciseNeither
Each dot is a reading; the centre is the true value.
Exam tip

A clock that is always exactly 5 minutes fast is precise (steady) but not accurate (wrong).

Conclusion

Precision is about consistency; accuracy is about correctness. A good measurement needs both.

Set B: More important long questions 12 questions

Long questions often set in board papers from this chapter, answered in the same full style.

Imp. LQ 1

What is measurement? Explain why we need standard units.

Answer

Definition

Definition
Measurement

The process of comparing an unknown quantity with a known, fixed standard quantity called a unit.

The two parts of a measurement

MeasurementNumber (magnitude)Unit
5 m5metre
250 g250gram
30 s30second
Remember

A measurement without a unit is meaningless: "the rod is 5 long" could mean 5 mm or 5 km.

Problems with early measurements

Long ago people measured with hand spans, arm lengths (cubits) and footsteps. Since every person's hand, arm and foot are different, the same object gave different measurements, which caused confusion in trade and building.

Need for standard units

Why standards matter
  • A standard unit means the same thing to everyone, everywhere.
  • Anyone measuring the same object gets the same result.
  • Trade is fair: a kilogram of sugar is the same in every shop.
  • Scientists in different countries can compare and share their results.

This is why the world uses the International System of Units (SI), with seven base units fixed by international agreement.

Imp. LQ 2

What are prefixes? Explain their use in measurement with examples.

Answer

Definition

Definition
Prefix

A word or symbol placed before a unit to multiply it by a power of ten.

Why prefixes are used

Very large and very small quantities are long and awkward to write. Writing 50 000 000 m or 0.000 04 m is slow and easy to get wrong. Prefixes make such values short and easy to read.

Without a prefixWith a prefix
50 000 000 m50 Mm (megametres)
5000 m5 km (kilometres)
0.001 m1 mm (millimetre)
0.000 004 s4 µs (microseconds)

Common prefixes

PrefixSymbolValue
gigaG10⁹
megaM10⁶
kilok10³
centic10⁻²
millim10⁻³
microµ10⁻⁶
nanon10⁻⁹

Examples of use

  • A millimetre (one thousandth of a metre) is handy for the thickness of a coin or a wire.
  • A kilometre (one thousand metres) is handy for the distance between cities.
  • A megawatt describes the output of a power station.
Exam tip

Capital and small letters matter: m = milli, M = mega.

Imp. LQ 3

What is scientific notation? Explain with examples.

Answer

Definition

Definition
Scientific notation (standard form)

A short way of writing a very large or very small number as N × 10ⁿ, where N is from 1 up to (but not including) 10 and n is a whole number.

N × 10ⁿ, 1 ≤ N < 10

Why it is used

Long strings of zeros take space, are hard to read and compare, and lead to mistakes in calculations. Powers of ten keep numbers short and make their size clear at a glance.

How to write a number in scientific notation

  1. Move the decimal point until only one non-zero digit is left before it.
  2. Count the number of places you moved it: that is n.
  3. Moved to the left (a big number): n is positive. Moved to the right (a small number): n is negative.

Examples

QuantityOrdinary formScientific notation
Distance from the Earth to the Sunabout 150 000 000 km1.5 × 10⁸ km
Speed of light300 000 000 m s⁻¹3.0 × 10⁸ m s⁻¹
Radius of a hydrogen atomabout 0.000 000 000 053 m5.3 × 10⁻¹¹ m
Thickness of a sheet of paper0.0001 m1 × 10⁻⁴ m
Remember

Scientific notation also shows the significant figures clearly: 5.00 × 10³ has three, 5 × 10³ has one.

Imp. LQ 4

Write a note on the metre rule. How is parallax error avoided?

Answer

The metre rule

A metre rule is a scale one metre long, marked in centimetres and millimetres. It is used in the laboratory to measure lengths such as the length of a table, a book or a rod.

Definition
Least count of a metre rule

1 mm (0.1 cm): the smallest length it can measure correctly.

How to measure a length

  1. Place the rule along the object, touching it.
  2. Line up the zero mark with one end of the object.
  3. Read the mark at the other end with your eye directly above it.
  4. The reading at the other end is the length.

Parallax error

If the scale is read from the side, the mark appears to shift and the object seems longer or shorter than it is. This is parallax error.

0123456789101112131415objectA: reads too muchB: correctC: reads too little
Only eye B, straight above the mark, reads the true length.
How to avoid it
  • Keep the eye directly above the mark, at right angles to the scale.
  • Keep the object touching the scale, or stand the rule on its edge so the marks touch the object.

If the end of the rule is worn

worn12345678910111213pencil: starts at 2.0 cm, ends at 9.5 cm
Start from a clear mark and subtract the two readings.
Imp. LQ 5

Describe the construction and working of Vernier Callipers.

Answer

Introduction

Vernier Callipers measure small lengths precisely, to 0.1 mm (0.01 cm): the diameter of a pipe or a coin, the inner size of a test tube, or the depth of a beaker.

Construction

  • Main scale: fixed, marked in millimetres.
  • Vernier scale: slides along the main scale; it is 9 mm long and divided into 10 equal divisions.
  • Outside jaws: one fixed, one sliding; they grip an object to measure its outer size.
  • Inside jaws: on the top; they fit inside an object to measure its inner size.
  • Depth rod (tail): slides out of the end to measure depth.
  • Lock screw: holds the vernier in place while you read it.
OutsidejawsInside jawsLock screwMain scaleVernier scale (slides)Depth rod
The parts of Vernier Callipers.

Least count

1 main scale division = 1 mm, and 10 vernier divisions = 9 mm, so 1 vernier division = 0.9 mm.

LC = 1 MSD − 1 VSD = 1 mm − 0.9 mm = 0.1 mm = 0.01 cm
or LC = 1 MSD ÷ number of vernier divisions = 1 mm ÷ 10

Working: taking a reading

  1. Close the jaws and check for zero error.
  2. Hold the object gently between the outside jaws.
  3. Main scale reading (MSR): read the main scale mark just before the vernier's zero.
  4. Vernier reading: find the vernier line (n) that lines up exactly with a main scale line.
  5. Reading = MSR + (n × LC); then correct for any zero error.
23main scale (cm)05710vernier scale: 10 divisions = 9 mm↑ zero just past 2.3
MSR = 2.3 cm and the 7th vernier line lines up.
Worked exampleReading from the diagram
  1. Reading = 2.3 cm + (7 × 0.01 cm).

Answer2.37 cm

Zero error and its correction

CaseWhat you see with the jaws closedZero error
No zero errorThe two zeros line up exactly0
PositiveVernier zero is to the right of the main zero+ (n × LC)
NegativeVernier zero is to the left of the main zero− (10 − n) × LC
Corrected reading = observed reading − zero error
Exam tip

Digital Vernier Callipers show the reading on a screen and have a least count of 0.01 mm.

Imp. LQ 6

Describe the construction and working of a micrometer screw gauge.

Answer

Introduction

A micrometer screw gauge measures very small lengths, to 0.01 mm: the diameter of a thin wire or the thickness of a thin sheet.

Construction

  • U-shaped frame that holds the other parts.
  • Anvil: fixed stud at one end; the object is placed against it.
  • Spindle: moves towards the anvil when the thimble is turned.
  • Sleeve: carries the main scale and a horizontal datum line.
  • Thimble: carries the circular scale, usually 50 or 100 divisions.
  • Ratchet: turns the thimble and slips (clicks) once the object is gripped, so it is never squeezed too hard.
object goes hereAnvilSpindleSleeve: main scale + datum lineThimble: circular scaleRatchetU-shaped frame
The parts of a micrometer screw gauge.

Pitch and least count

Definition
Pitch

The distance the spindle moves in one complete turn of the thimble, for example 0.5 mm or 1 mm.

LC = pitch ÷ number of circular scale divisions
0.5 mm ÷ 50 = 0.01 mm, or 1 mm ÷ 100 = 0.01 mm

Working: taking a reading

  1. Close the gauge and check for zero error.
  2. Place the object between the anvil and spindle; turn the ratchet until it clicks.
  3. Main scale reading (MSR): the last mark visible on the sleeve.
  4. Circular scale reading (CSR): the thimble line that meets the datum line.
  5. Reading = MSR + (CSR × LC); then correct for any zero error.
0123sleeve: main scale (mm), datum line657075← on datum linethimble: circular scale
MSR = 3 mm and line 70 meets the datum line.
Worked exampleReading from the diagram
  1. Reading = 3 mm + (70 × 0.01 mm).

Answer3.70 mm

Zero error

Circular zero, with the gauge closedTypeCorrection
On the datum lineNo zero errorNone
Below the datum linePositive (reads too much)Subtract it
Above the datum lineNegative (reads too little)Add its size
Remember

Always use the ratchet, not the thimble, for the final turn; otherwise you squeeze the object and get a wrong reading.

Imp. LQ 7

Write a note on the physical balance. How is it used?

Answer

What it is

A physical balance is a sensitive beam balance used in the laboratory to measure the mass of an object. It works on the principle of a lever: the beam balances when the masses on the two pans are equal.

Mass and weight

In daily life we say "weight" for mass, but in physics they differ: mass is the quantity of matter (kg), while weight is the force of gravity on it (N), measured with a spring balance. A balance compares masses, so it gives the same reading anywhere.

Steps for using it

  1. Level the base: turn the levelling screws until the plumb line hangs exactly over its mark.
  2. Check the beam: raise the beam with the knob; the pointer should rest at zero. If not, adjust the balancing screws.
  3. Place the object on the left pan.
  4. Add standard masses to the right pan with forceps, never with fingers.
  5. Balance it: adjust the masses until the pointer stays at zero, or swings equally either side of it.
  6. Read the mass: the total of the standard masses on the right pan is the mass of the object.
Exam tip

Lower the beam before adding or removing anything from the pans, so the knife-edges are not damaged.

Imp. LQ 8

Write a note on the stopwatch.

Answer

What it is

A stopwatch measures the time taken by an event, for example the time for a pendulum to swing or for a runner to finish a race.

Mechanical stopwatch

It has two hands: one for seconds and one for minutes. The dial is divided into 30 big divisions, each split into 10 small divisions, so one small division is 0.1 s: its least count.

Digital stopwatch

It shows the time as numbers on a screen and usually reads to 0.01 s, so it is more precise.

MechanicalDigital
Works bySpring and gearsElectronic circuit
DisplayHands on a dialNumbers on a screen
Least count0.1 s0.01 s
PowerWound by handBattery

How to use it

  1. Press the knob (button) to start the watch as the event begins.
  2. Press it again to stop it when the event ends.
  3. Note the reading, then press once more to reset to zero.
Remember

Human reaction time (about 0.2 s) limits any hand-operated stopwatch, so time several repeats and take the average.

Imp. LQ 9

Describe the measuring cylinder. How is the volume of an irregular solid found with a measuring cylinder and a displacement can?

Answer

Measuring cylinder

A measuring cylinder is a tall glass or transparent plastic cylinder marked in millilitres (mL) or cubic centimetres (cm³). It measures the volume of liquids, and of solids that do not dissolve. 1 mL = 1 cm³.

Reading the meniscus

Place the cylinder on a level surface and bring your eye level with the liquid surface. Water curves down (concave), so read the bottom of the curve; mercury curves up (convex), so read the top.

Eye too high: reads too muchEye level with the bottomEye too low: reads too littleRead here: the lowestpoint of the meniscus
Eye level with the bottom of the meniscus.

Method 1: measuring cylinder

Worked exampleVolume of a stone
  1. Pour water into the cylinder and note the level: V₁ = 50 mL.
  2. Tie the stone with a thread and lower it gently into the water; note the new level: V₂ = 75 mL.
  3. Volume of stone = V₂ − V₁ = 75 − 50.

Answer25 mL = 25 cm³

Method 2: displacement can (for a large solid)

  1. Place the displacement can on a level table.
  2. Fill it with water until water starts flowing out of the spout; wait until it stops.
  3. Place an empty measuring cylinder under the spout.
  4. Lower the solid, tied with a thread, gently into the can.
  5. The solid pushes out (displaces) its own volume of water into the cylinder.
  6. Read the volume of the collected water: this is the volume of the solid.
Method 1: measuring cylinderV₁ = 50 mLbeforeV₂ = 75 mLstone insideMethod 2: displacement cancan filled to the spoutcollect water
Both methods side by side.
Imp. LQ 10

Explain the concept of uncertainty in measurement.

Answer

No measurement is perfect

Except for counting, every measurement has some uncertainty: a range within which the true value lies. One big cause is the instrument itself, which can only read to its smallest division.

Uncertainty and least count

Suppose the end of a line lies between the 10.3 cm and 10.4 cm marks of a metre rule. We record the nearer mark:

  • If the end has not reached halfway between the marks, record the lower mark (10.3 cm).
  • If it has reached or passed halfway, record the higher mark (10.4 cm).

Either way, the true length could be up to half a division away from what we wrote: the uncertainty is about ± 0.05 cm, half the least count. Many books simply quote it as ± one least count (± 0.1 cm) to be safe.

Worked exampleWriting a measurement with its uncertainty
  1. Length read on a metre rule: 10.3 cm.
  2. Least count = 0.1 cm.

Answer10.3 ± 0.1 cm

Uncertainty and significant figures

Significant figures show uncertainty too: 10.3 cm (3 significant figures) means the last digit, 3, is the doubtful one. A more precise instrument lets us record more significant figures.

Remember

A smaller least count means a smaller uncertainty.

Imp. LQ 11

What are significant figures? Explain the rules for counting them with examples.

Answer

Definition

Definition
Significant figures

In a measurement, all the accurately known digits plus the first doubtful digit.

Worked exampleWhere the doubtful digit comes from
  1. A rod's end lies between the 4.6 cm and 4.7 cm marks.
  2. One student writes 4.6 cm, another 4.7 cm: both agree on the 4; the second digit is estimated.
  3. So the measurement has 2 significant figures: one certain digit and one doubtful digit.

Rules

RuleExampleSignificant figures
All non-zero digits are significant5.67 m3
Zeros between non-zero digits are significant5.06 m3
Leading zeros (before the first non-zero digit) are not significant0.0034 m2
Trailing zeros after a decimal point are significant2.40 mm3
In scientific notation, all digits before × 10ⁿ are significant3.50 × 10⁻⁴ m3

Significant figures in calculations

OperationRuleExample
Add or subtractKeep the fewest decimal places12.321 − 10.3 = 2.0
Multiply or divideKeep the fewest significant figures2.5 × 1.23 = 3.1
Remember

A zero like the one in 5000 is unclear; write 5 × 10³ or 5.00 × 10³ to show exactly how many figures are significant.

Imp. LQ 12

Explain the rules for rounding off numbers in scientific measurements.

Answer

Why we round off

A calculation often gives more digits than the measurements justify. We round the answer to the right number of significant figures so it does not claim more precision than we have.

Rules

  1. If the digit after the last one kept is less than 5, leave the last kept digit unchanged.
  2. If it is more than 5, increase the last kept digit by 1.
  3. If it is exactly 5: increase the last kept digit if it is odd, and leave it if it is even.

Examples

NumberRound toResultReason
2.512 × 10³ m2 significant figures2.5 × 10³ mNext digit 1 is less than 5
3.4567 × 10⁴ kg3 significant figures3.46 × 10⁴ kgNext digit 6 is more than 5
4.45 × 10² m2 significant figures4.4 × 10² mExactly 5, and 4 is even
4.55 × 10² m2 significant figures4.6 × 10² mExactly 5, and 5 is odd
Exam tip

Some teachers always round 5 upward. Ask which rule your examiner uses, and use it every time.

Part 6of 7

Numericals Solved Step by Step

Each numerical in the order you write it in the exam: Given Data, To Find, Formula, Calculation, Result.

Only the numericals on one page →
Numerical 1.1

Find the number of seconds in (a) one day (b) one week (c) one month. Express each answer using a suitable prefix.

Given Data

  • 1 hour = 3600 s
  • 1 day = 24 hours
  • 1 month = 30 days (taken)

To Find

  • Seconds in (a) a day (b) a week (c) a month, written with SI prefixes

Formula

seconds = days × 24 × 3600

Calculation

  1. One day: 24 × 3600 s = 86 400 s. Since 1 ks = 1000 s, this is 86.4 ks.
  2. One week: 7 × 86 400 s = 604 800 s = 604.8 ks.
  3. One month: 30 × 86 400 s = 2 592 000 s. Since 1 Ms = 10⁶ s, this is 2.592 Ms.
Result

(a) 86.4 ks (b) 604.8 ks (c) 2.592 Ms

Note: Some keys print "Ks". The symbol for kilo is a small k, so it is ks.

Numerical 1.2

Write the seconds in one day, one week and one month in scientific notation.

Given Data

  • 1 day = 86 400 s
  • 1 week = 604 800 s
  • 1 month = 2 592 000 s (from Numerical 1.1)

To Find

  • Each answer of Numerical 1.1 in scientific notation

Formula

N × 10ⁿ, 1 ≤ N < 10

Calculation

  1. 86 400 s: move the point 4 places left, so 8.64 × 10⁴ s.
  2. 604 800 s: move the point 5 places left, so 6.048 × 10⁵ s.
  3. 2 592 000 s: move the point 6 places left, so 2.592 × 10⁶ s.
Result

8.64 × 10⁴ s, 6.048 × 10⁵ s, 2.592 × 10⁶ s

Numerical 1.3

Solve: (a) 4 × 10⁻⁴ kg + 3 × 10⁻⁵ kg (b) 5.4 × 10⁻⁶ m − 3.2 × 10⁻⁵ m

Given Data

  • (a) 4 × 10⁻⁴ kg and 3 × 10⁻⁵ kg
  • (b) 5.4 × 10⁻⁶ m and 3.2 × 10⁻⁵ m

To Find

  • (a) the sum (b) the difference, in scientific notation

Formula

Make the powers of ten equal, then add or subtract the numbers

Calculation

  1. To add or subtract, first make the powers the same.
  2. (a) Write 3 × 10⁻⁵ as 0.3 × 10⁻⁴. Then (4 + 0.3) × 10⁻⁴ = 4.3 × 10⁻⁴ kg.
  3. (b) Write 5.4 × 10⁻⁶ as 0.54 × 10⁻⁵. Then (0.54 − 3.2) × 10⁻⁵ = −2.66 × 10⁻⁵ m.
Result

(a) 4.3 × 10⁻⁴ kg (b) −2.66 × 10⁻⁵ m

Note: In (b) the minus sign just shows the second length is the larger one. With strict rounding to 1 decimal place the answer is −2.7 × 10⁻⁵ m.

Numerical 1.4

Solve: (a) (5 × 10⁴ m) × (3 × 10⁻² m) (b) (6 × 10⁸ kg) ÷ (3 × 10⁴ m³)

Given Data

  • (a) 5 × 10⁴ m and 3 × 10⁻² m
  • (b) 6 × 10⁸ kg and 3 × 10⁴ m³

To Find

  • (a) the product (b) the quotient, in scientific notation

Formulas

10ᵃ × 10ᵇ = 10ᵃ⁺ᵇ
10ᵃ ÷ 10ᵇ = 10ᵃ⁻ᵇ

Calculation

  1. (a) Multiply the numbers: 5 × 3 = 15. Add the powers: 4 + (−2) = 2. So 15 × 10² m² = 1.5 × 10³ m².
  2. (b) Divide the numbers: 6 ÷ 3 = 2. Subtract the powers: 8 − 4 = 4. So 2 × 10⁴ kg m⁻³.
Result

(a) 1.5 × 10³ m² (b) 2 × 10⁴ kg m⁻³

Numerical 1.5

Solve: (3 × 10² kg) × (4.0 km) ÷ (5 × 10² s²), and give the answer in base units.

Given Data

  • 1 km = 10³ m

To Find

  • The value in base units, in scientific notation

Formula

10ᵃ ÷ 10ᵇ = 10ᵃ⁻ᵇ

Calculation

  1. Multiply the top: 3 × 4.0 = 12, so the top is 12 × 10² kg km.
  2. Divide: 12 × 10² ÷ (5 × 10²) = 2.4, since 10² ÷ 10² = 1. The result is 2.4 kg km s⁻².
  3. Change km to m: 2.4 × 10³ kg m s⁻².
Result

2.4 × 10³ kg m s⁻²

Numerical 1.6

How many significant digits are in: (a) 0.0045 m (b) 2.047 m (c) 3.40 m (d) 3.420 × 10⁴ m?

Given Data

  • (a) 0.0045 m (b) 2.047 m (c) 3.40 m (d) 3.420 × 10⁴ m

To Find

  • The number of significant figures in each

Calculation

  1. (a) Zeros at the start do not count; 4 and 5 remain, so 2.
  2. (b) The zero between 2 and 4 counts, so 4.
  3. (c) The end zero after the decimal counts, so 3.
  4. (d) Count only the digits in 3.420, including the end zero, so 4.
Result

(a) 2 (b) 4 (c) 3 (d) 4

Numerical 1.7

Write in scientific notation: (a) 0.0035 m (b) 206.4 × 10² m

Given Data

  • (a) 0.0035 m (b) 206.4 × 10² m

To Find

  • Each in scientific notation

Formula

N × 10ⁿ, 1 ≤ N < 10

Calculation

  1. (a) Move the point 3 places right to get 3.5. The power is −3, so 3.5 × 10⁻³ m.
  2. (b) 206.4 = 2.064 × 10², so 206.4 × 10² = 2.064 × 10² × 10².
  3. Add the powers: 2 + 2 = 4, so 2.064 × 10⁴ m.
Result

(a) 3.5 × 10⁻³ m (b) 2.064 × 10⁴ m

Numerical 1.8

Rewrite using suitable prefixes: (a) 5.0 × 10⁴ cm (b) 580 × 10² g (c) 45 × 10⁻⁴ s

Given Data

  • (a) 5.0 × 10⁴ cm (b) 580 × 10² g (c) 45 × 10⁻⁴ s

To Find

  • Each with a suitable prefix

Formula

1 m = 100 cm; 1 km = 10³ m; 1 kg = 10³ g; 1 ms = 10⁻³ s

Calculation

  1. (a) 5.0 × 10⁴ cm = 50 000 cm. Divide by 100 to get 500 m, then by 1000 to get 0.50 km.
  2. (b) 580 × 10² g = 58 000 g. Divide by 1000 to get 58 kg.
  3. (c) 45 × 10⁻⁴ s = 4.5 × 10⁻³ s. Since 10⁻³ s = 1 ms, this is 4.5 ms.
Result

(a) 0.50 km (b) 58 kg (c) 4.5 ms

Numerical 1.9

Light travels at 3.0 × 10⁸ m s⁻¹. How far does it go in one year (one light year)?

Given Data

  • v = 3.0 × 10⁸ m s⁻¹
  • t = 1 year = 365 days

To Find

  • Distance light travels in one year (1 light year)

Formula

S = v × t

Calculation

  1. Time in seconds: t = 365 × 24 × 3600 s = 31 536 000 s.
  2. Distance = speed × time = v × t.
  3. Distance = (3.0 × 10⁸) × 31 536 000 = 9.4608 × 10¹⁵ m.
Result

1 light year = 9.4608 × 10¹⁵ m ≈ 9.5 × 10¹⁵ m (2 significant figures)

Numerical 1.10

The density of mercury is 13.6 g cm⁻³. Express it in kg m⁻³.

Given Data

  • 1 g = 10⁻³ kg
  • 1 cm = 10⁻² m, so 1 cm³ = 10⁻⁶ m³

To Find

  • Density of mercury in kg m⁻³

Formulas

1 g = 10⁻³ kg
1 cm³ = 10⁻⁶ m³

Calculation

  1. Put the conversions in: 13.6 g cm⁻³ = 13.6 × 10⁻³ kg ÷ 10⁻⁶ m³.
  2. Subtract the powers: −3 − (−6) = +3, so 13.6 × 10³ kg m⁻³.
  3. In scientific notation: 1.36 × 10⁴ kg m⁻³.
Result

13.6 g cm⁻³ = 1.36 × 10⁴ kg m⁻³

Note: Shortcut to remember: 1 g cm⁻³ = 1000 kg m⁻³.

Part 7of 7

Revision, Practice and Self-Test

Use this the night before the test.

One-page formula sheet

Vernier least count
LC = 1 MSD − 1 VSD = 1 MSD ÷ vernier divisions
Vernier reading
Reading = MSR + (n × LC)
Screw gauge least count
LC = pitch ÷ circular scale divisions
Screw gauge reading
Reading = MSR + (CSR × LC)
Zero error (positive)
+ (n × LC)
Zero error (negative, Vernier)
− (10 − n) × LC
Zero error (negative, screw gauge)
− (100 − n) × LC
Corrected reading
Observed reading − zero error
Volume of irregular solid
V = V₂ − V₁
Volume
1 mL = 1 cm³; 1 L = 1000 cm³; 1 m³ = 1000 L
Average
Sum of readings ÷ number of readings
Scientific notation
N × 10ⁿ, where 1 ≤ N < 10
Powers of ten
10ᵃ × 10ᵇ = 10ᵃ⁺ᵇ; 10ᵃ ÷ 10ᵇ = 10ᵃ⁻ᵇ

Key definitions 19 terms

Physics
The branch of science that studies matter, energy and how they act on each other.
Physical quantity
Anything we can measure with an instrument and write as a number with a unit. Examples: length, mass, time, temperature.
Non-physical quantity
Something with no instrument or standard unit, so it cannot be measured. Examples: love, beauty, honesty, trust. Colour, as a person sees it, is treated as non-physical in your book because it depends on who is looking.
Measurement
Comparing an unknown quantity with a fixed standard, called a unit.
Base quantities
The seven quantities that stand on their own and are not made from other quantities. Each has an SI base unit (SI = International System of Units).
Derived quantities
Quantities made by multiplying or dividing base quantities. Their units are derived units.
Prefix
A word placed before a unit to show a power of ten, so very large or very small numbers are easy to read. 5000 m becomes 5 km.
Scientific notation
Writing a number as N × 10ⁿ, where N is from 1 up to (but not including) 10 and the power n is a whole number.
Least count (LC)
The smallest length an instrument can read correctly. A smaller least count means a more precise instrument.
Parallax error
The error when a scale is read from the side, so the mark seems to shift. Keep your eye straight above the mark and the object close to the scale.
Zero error
When the jaws are fully closed the two zeros should line up exactly. If they do not, every reading is off by the same amount.
Pitch
The distance the spindle moves in one full turn of the thimble.
Mass
The amount of matter in an object. Its SI unit is the kilogram, and it is measured with a balance.
Volume
The space an object takes up. A measuring cylinder measures the volume of a liquid.
Meniscus
The curved surface of a liquid in a narrow tube. Read water at the bottom of the curve; mercury curves up, so read the top of its curve.
Error
The difference between the measured value and the true value. No measurement is perfect.
Significant figures
The digits in a measurement we can trust: all the certain digits plus the first doubtful digit. They show how carefully something was measured.
Precision
How close repeated readings are to each other. It depends on the instrument: a smaller least count gives more precision.
Accuracy
How close a reading is to the true value. It depends on careful work, a correct instrument and more significant figures.

Common mistakes to avoid

  • Forgetting the unit in the final answer.
  • Mixing up m (milli) and M (mega).
  • Writing a Vernier reading with the wrong number of decimal places. In cm it must have 2.
  • Counting the zeros at the start of 0.0045 as significant.
  • Adding numbers in scientific notation before making the powers equal.
  • Using the wrong sign when correcting a zero error.
  • Reading a measuring cylinder from above or below eye level.

Extra practice tap a question to see its answer

  1. Convert 2.5 km into metres.Show answer

    2.5 × 1000 = 2500 m

  2. Convert 450 mg into grams.Show answer

    450 × 0.001 = 0.45 g

  3. Write 0.000072 m in scientific notation.Show answer

    7.2 × 10⁻⁵ m

  4. Vernier Callipers: MSR = 4.2 cm and the 6th line coincides. Find the reading.Show answer

    4.2 + (6 × 0.01) = 4.26 cm

  5. The reading above has a zero error of +0.02 cm. Find the corrected reading.Show answer

    4.26 − 0.02 = 4.24 cm

  6. A Vernier reading of 5.12 cm has a zero error of −0.03 cm. Find the corrected reading.Show answer

    5.12 − (−0.03) = 5.15 cm

  7. Screw gauge: MSR = 2.5 mm, CSR = 36, LC = 0.01 mm. Find the reading.Show answer

    2.5 + (36 × 0.01) = 2.86 mm

  8. A screw gauge has a pitch of 0.5 mm and 50 circular divisions. Find its least count.Show answer

    0.5 ÷ 50 = 0.01 mm

  9. How many significant figures are in 50.20?Show answer

    4: the middle zero and the end zero both count

  10. Round 6.782 to 2 significant figures.Show answer

    6.8

  11. Add 12.1 cm + 3.45 cm with correct decimal places.Show answer

    15.55, written as 15.6 cm (1 decimal place)

  12. Multiply 2.5 × 1.23 with correct significant figures.Show answer

    3.075, written as 3.1 (2 significant figures)

  13. A stone raises the water level in a cylinder from 62 mL to 80 mL. Find its volume.Show answer

    80 − 62 = 18 mL = 18 cm³

  14. Find the average of 20.1 cm, 20.3 cm and 20.2 cm.Show answer

    60.6 ÷ 3 = 20.2 cm

Final self-test

Final self-test: all 24 MCQs, no answers

Give yourself 25 minutes. Pick one option for each question, then submit to see your score and which questions to revise. Any question you get wrong tells you which topic to read again.

End of Part 7Back to Part 1 ↑
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Turning Effect of Forces
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Mechanical Properties of Matter
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Thermal Properties of Matter
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Magnetism
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Nature of Science
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