MDCAT Physics — Dawn of Modern Physics
Dawn of Modern Physics is a core Physics topic in the PMDC MDCAT syllabus, covering 6 subtopics. Below are the subtopics to revise, how often the topic appears in past papers, and real past-paper MCQs to try.
Subtopics (6)
- Black Body Radiation (Wien's Law)
- Lasers (Working Principle and Uses)
- Modern Physics
- Pair Production
- Photoelectric
- Quantum Theory and Radiation (Photons)
How Dawn of Modern Physics is tested
Across the 16 MDCAT past papers on ParhaiKrlo, Dawn of Modern Physics accounts for 52 questions. It appears in 14 of them, about 3.7 questions a paper. The heaviest was MDCAT 2012, with 7 questions, and the most recent is MDCAT 2024, with 1.
| Paper | Questions |
|---|---|
| MDCAT 2024 | 1 |
| MDCAT 2023 | 2 |
| MDCAT 2022 | 4 |
| MDCAT 2019 | 2 |
| MDCAT 2018 | 2 |
| MDCAT 2017 | 3 |
| MDCAT 2016 | 1 |
| MDCAT 2015 | 3 |
| MDCAT 2013 | 6 |
| MDCAT 2012 | 7 |
| MDCAT 2011 | 4 |
| MDCAT 2010 | 5 |
| MDCAT 2009 | 5 |
| MDCAT 2008 | 7 |
Dawn of Modern Physics MCQs from the MDCAT past papers
Try each one before opening the answer. Each comes with a short explanation.
- Q1 · MDCAT 2024 · Dawn of Modern Physics
The value of Planck constant is
- A.6.63×10⁻³⁴ J s
- B.6.63×10³⁴ J s
- C.6.63×10⁻³⁴ J s⁻¹
- D.6.63×10³⁴ J s⁻¹
Show answer
Answer: A. 6.63×10⁻³⁴ J s — Planck's constant is 6.63×10⁻³⁴ J·s.
- Q2 · MDCAT 2023 · Dawn of Modern Physics
In Compton effect, the incident photon when compared to the scattered photon is of:
- A.Greater energy
- B.Greater frequency
- C.Greater energy and momentum
- D.Equal energy
Show answer
Answer: C. Greater energy and momentum — In the Compton effect, the incident photon has greater energy and momentum than the scattered photon, having transferred some to the electron it collided with.
- Q3 · MDCAT 2022 · Dawn of Modern Physics
If electron, proton, neutron, and alpha particle have same velocity, which of them has the shortest wavelength?
- A.Electron
- B.Proton
- C.Neutron
- D.Alpha particle
Show answer
Answer: D. Alpha particle — De Broglie wavelength λ=h/(mv) is inversely proportional to mass, so at equal velocity, the heaviest particle (the alpha particle) has the shortest wavelength.